2x^2-162x-720=0

Solution for 2x^2-162x-720=0 equation:

2x^2-162x-720=0

a = 2; b = -162; c = -720;
Δ = b2-4ac
Δ = -1622-4·2·(-720)
Δ = 32004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32004}=\sqrt{36*889}=\sqrt{36}*\sqrt{889}=6\sqrt{889}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-162)-6\sqrt{889}}{2*2}=\frac{162-6\sqrt{889}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-162)+6\sqrt{889}}{2*2}=\frac{162+6\sqrt{889}}{4}
$